H_(2)O_(2) এর একটি 5.0 মিলি দ্রবণ অ্যাসিডিফাইড KI দ্রবণ থেকে 0.508 গ্রাম আয়োডিনকে মুক্ত করে। ক্যালকু...

^^_(m)^(0)H_(2)O is equal to ___

Which equilibrium constant(s) or ratio of equilibrium contants should be used to calculate the pH of 1.00L of each of the following solutions? a. KOH b. NH_(3) c. HC_(2)H_(3)O_(2) d. HC_(2)H_(3)O_(2) +NaC_(2)H_(3)O_(2) e. KC_(2)H_(3)O_(2) f. 0.01 mol HC_(2)H_(3)O_(2) + 0.050 mol NaOh g. H_(2)S h. 0.01NH_(4)CI + 0.50mol NaOH i. 0.010 mol HC_(2)H_(3)O_(2) + 0.10mol NaOH

20 " mL of " H_(2)O_(2) is reacted completely with acidified K_(2)Cr_(2)O_(7) solution 40 " mL of " K_(2)Cr_(3)O_(7) solution was required to oxidised the H_(2)O_(2) completely. Also, 2.0 " mL of " the same K_(2)Cr_(2)O_(7) solution required 5.0 " mL of " a 1.0 M H_(2)C_(2)O_(4) solution to reach equivalence point. Which of the following statements is/are correct?

A 5-0cm^(3) solutions of H_(2)O_(2) liberates of 0.508g of iodine from acidified KI solution. Calculate the volume strength of H_(2)O_(2) at N.T.P.