यदि cos(alpha+beta)=0 तो sin(alpha-beta) | CLASS 10 | प्रश्न पत्र 2022 शिफ्ट 2 | MATHS | Doubtnu...

If cos(alpha+beta)=0 then sin(alpha+2beta)=

If cos(alpha+beta)=0 then sin^(2)alpha+sin^(2)beta

(cos alpha + cos beta) ^ (2) + (sin alpha + sin beta) ^ (2) =

If cos alpha+cos beta=0=sin alpha+sin beta then cos2 alpha+cos2 beta=

If cos alpha+cos beta=0=sin alpha+sinbeta, then cos2alpha+cos 2beta=

If cos (alpha+beta)=0 , then sin(alpha-beta) canbe reduced to : (a) cosbeta (b) cos2beta ( c) sinalpha (d) sin2alpha

(cos alpha-cos beta) ^ (2) + (sin alpha-sin beta) ^ (2) = 4 (sin ^ (2) (alpha-B)) / (2)