गुणनखंड कीजिए : 16x^2-25y^2 | 8 | गुणनखंड | MATHS | MBD HINDI-HARYANA BOARD | Doubtnut

25a^2-9 is factored as: 25a^2-9 का गुणनखंड होगा :

The foci of 16x ^(2) + 25 y^(2) =400 are

int(dx)/((16x^(2)-25))

(i) 7x^(2) + 16x - 15 = 0 (ii) 5y^(2)+ 8y - 21 = 0

Foci of the ellipse 16x^(2)+25y^(2)=400 are

int(x^3)/(16x^8-25)dx=

Statement-I The line 4x-5y=0 will not meet the hyperbola 16x^(2)-25y^(2)=400 . Statement-II The line 4x-5y=0 is an asymptote ot the hyperbola.

Combined equation of pair of tangent to the hyperbola x^(2) - y^(2) = 8 " is " 8x^(2) - 7y^(2) - 16x + 8 = 0 and equation of chord of contect is x = lambda , then value of lambda is __________

The tangent at any point on the ellipse 16x^(2)+25y^(2) = 400 meets the tangents at the ends of the major axis at T_(1) and T_(2) . The circle on T_(1)T_(2) as diameter passes through