প্রদত্ত যে `vec(A)+vec(B)+vec(C )=vec(0)`। তিনটি ভেক্টরের মধ্যে দুটির মাত্রা সমান এবং টি...

If vec(A)+vec(B)+vec(C )=0 then vec(A)xx vec(B) is

If vec(a)=vec(b)+vec(c ) , then |vec(a)|=|vec(b)+vec(c )| .

(vec a-vec b)*{(vec b-vec c)xx(vec c-vec a)}=0

If vec a + vec b + vec c = 0 then vec a xxvec b =

If vec( A) + vec(B) =vec( C ) , and | vec(A)| =2 | vec( B) | and vec( B). vec( C ) = 0 , then

The vector vec(A),vec(B) and vec( C ) are such that |vec(A)|=|vec(B)|,|vec( C )| = sqrt2|vec(A)| and vec(A) + vec(B) + vec( C ) =0. The angles between vec(A) and vec(B), vec(B) and vec( C ) respectively are

Prove that (vec a-vec b)(vec b-vec c)xx(vec c-vec a)=0

[vec(a)vec(b)vec(c )]=[vec(b)vec(c )vec(a)]=[vec(c )vec(a)vec(b)] .

The vectors vec(a), vec(b), vec(c ) and vec(d) are such that vec(a) xx vec(b) = vec(c ) xx vec(d) and vec(a) xx vec(c )= vec(b) xx vec(d) . Which of the following is/are correct? 1. (vec(a)- vec(d)) xx (vec(b) - vec(c ))= vec(0) 2. (vec(a) xx vec(b))xx (vec(c ) xx vec(d))= vec(0) Select the correct answer using the codes given below

If vec(a), vec(b), vec(c ) are three vectors such that vec(a)+vec(b)+vec(c )=0 , then prove that : vec(a)xx vec(b)=vec(b)xx vec(c )=vec(c )xx vec(a) and hence, show that [vec(a)vec(b)vec(c )]=0 .