ভরের দুটি বস্তু `m_1 এবং m_2` একটি হালকা স্ট্রিং দ্বারা সংযুক্ত

Two bodies of masses m_1 and m_2(

If m+ (1)/(m-2)=4 , find m^(2) + m+1 =?

If y+3=m_1(x+2) and y+3=m_2(x+2) are two tangents to the parabola y_2=8x , then (a)m_1+m_2=0 (b) m_1+m_2=-1 (c)m_1+m_2=1 (d) none of these

If the equations ax^2 + 2hxy+by^2 =0 and y^2 - (m_1 + m_2) xy+m_1 m_2 x^2 =0 represent the same curve, find m_1 +m_2 and m_1 m_2 .

In figure, find the velocity of m_1 in ms^-1 when m_2 falls by 9m . Given m_1=m , m_2=2m (take g=10ms^-2 ).

If m+ (1)/(m+2)=-4 , find m^(2) + m+1 =?

Two spherical bodies of mass m_1 & m_2 are having radius 1 m & 2 m respectively. The gravitational field of the two bodies with their radial distance is shown below. The value of (m_1)/(m_2) is -

Consider the case of two bodies of masses m_(1) and m_(2) which are connected by light inextensible string passing over a light smooth pulley as shown in the figure. The expression for acceleration of the system and tension of the string are expressed below under different situations: (i) when m_(1) gt m_(2) . In this case a=((m_(1)-m_(2))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g (ii) when m_(2) gt m_(1) . In this case a=((m_(2)-m_(1))/(m_(1)+m_(2)))g and T=((2m_(1)m_(2))/(m_(1)+m_(2)))g (iii) When m_(1)=m_(2)=m . In this case a = 0, T = mg What is the tension in the string?