চিত্রে `OA**OB=OC** OD`। দেখান যে `/_A=/_C` এবং `/_B=/_D`....

In figure OA*OB=OC*OD. Show that /_A=/_C and /_B=/_D

/_A+/_B+/_C+/_D+/_E=

In Fig.4.126,(OA)/(OC)=(OD)/(OB) .Prove that /_A=/_C and /_B=/_D.( FIGURE )

In the given figure, rays OA, OB, OC and OD are such that /_AOB = 50^(@) , /_ BOC = 90^(@) , /_ COD = 70^(@) , and /_ AOD = x^(@) . Then, the value of x is

In the given figure,rays OA, OB, OC and OD are such that angleAOB=56^(@) , angleBOC=100^(@) , angleCOD=x^(@) and angleDOA=74^(@) ,Find the value of x .

In Figure,rays OA,OB,OC, OD and OE have the common end point O .Show that /_AOB+/_BOC+/_COD+/_DOE+/_EOA=360^(@)

ABCD is a quadrilateral.E is the point of intersection of the line joining the midpoints of the opposite sides.If O is any point and vec OA+vec OB+vec OC+vec OD=xvec OE, then x is equal to a.3 b.9 c.7 d.4

In the following figure the radii (OA and OD) are 2 cm and /_\ABO and /_\DCO are right angle triangles. Also, OB =sqrt2 cm and OC = 1 cm. Find the area of the shaded region in the circle.

Let overset(to)(OA) = overset(to)(a), overset(to)(OB)= 10overset(to)(a) + 2overset(b) " and " overset(to)(OC)=overset(to)(b) where O,A and C are non-collinear points . Let P denotes the area of the quadrilateral OABC and let q denots the area of the parallelogram with OA and OC as adjacent sides. If p =kq , then h=........

If OA=vec a;OB=vec b;OC=2a+3b,OD=a-2, the length of OA is three xx the length of OB and OA is perpendicular to DB, then (BD xx AC).(OD xx OC) is