सिद्ध कीजिए- DeltaH=DeltaU+PDeltaV | 11 | रासायनिक ऊष्मागतिकी | CHEMISTRY | YUGBODH | Doubtnut

While doing an experiment on bomb calorimeter, a student made the following statement : DeltaH = DeltaU + pDeltaV Since in the experiment DeltaV =0 hence DeltaH = DeltaU .Is the student right or wrong? Justify.

Which of the following options correctly represent trure//false nature of statements? Statement-I: deltaH=deltaU+PdeltaV "for all processes" Statements-II: For a reaction involving only ideakl gas, DeltaH_(reaction) will be independent of the pressure at which reactants and products are taken. Statements-III: Heat taken from a thermal reservoir can be completely converted at work without liberating some heat at lower temperature. Statement-IV: For a chemical reaction, G at equillibrium will be zero.