"यदि `A=[(1, 2 ,2 ),(2 ,1 ,2),( 2 ,2, 1)]` , तो साबित करें कि `A^2-4A-5I=O` ."

If A=|(1,2,2),(2,1,2),(2,2,1)|, verifty that A^2-4A-5I-5I=0

If A=[{:(1,2,2),(2,1,2),(2,2,1):}] , prove that A^(2)-4A-5I=O and hence, obtain A^(-1) .

If A=[[1,2,2], [2,1,2],[2,2,1]] then A^(2)-5I=

If A=[(1,2,2),(2,1,2),(2,2,1)] then (A) A^-1= 1/5(A-4I_3) (B) A^2-4A-5I_3=0 (C) A^2 is invertible (D) A^3 is non invertible

If A=[[1,2,22,1,22,2,1]], then prove that A^(2)-4A-5I,=O

If A=|{:(1,2,2),(2,1,2),(2,2,1):}| , then show that A^(2)-4A-5I_(3)=0 . Hemce find A^(-1) .

If A = ({:( 1,2,3),( 2,1,2),( 2,2,1) :}) and A^(2) -4A -5l =O where I and O are the unit matrix and the null matrix order 3 respectively if , 15A^(-1) =lambda |{:( -3,2,3),(2,-3,2),(2,2,-3):}| then the find the value of lambda

Let A=[1 2 2 2 1 2 2 2 1] . Then A^2-4A-5I_3=O b. A^(-1)=1/5(A-4I_3) c. A^3 is not invertible d. A^2 is invertible

If A=[[2, 2, 1], [1, 3, 1], [1, 2, 2]], and A^(-1)+(A-5I)(A-I)^(2)=