For two resistors R_1 and R_2, connected in parallel, find the relative error in their equivalen...

If two resistors of R_(1) and R_(2) ohms are connected in parallel in an electric circuit to make an R ohm resistor, the value of R can be found from the equation, (1)/(R)=(1)/(R_(1))+(1)/(R_(2)) If R_(1) is decreasing at the rate of 1 ohm/sec and R_(2) i increasing at the rate of 0.5 ohm/sec, at what rate is R changing when R_(1)=75 ohm and R_(2)=50 ohm ?

If resistors of resistance R_(1) and R_(2) are connected in parallel,then resultant resistance is "

When two resistors of resistances R_1 and R_2 are connected in parallel, the net resistance is 3 Omega . When connected in series, its value is 16 Omega . Calculate the values of R_1 and R_2 .

Two resistance R_(1) and R_(2) are connected in (i) series and (ii) parallel. What is the equivalent resistance with limit of possible percentage error in each case of R_(1)=5.0+-0.2Omega and R_(2)=10.0+-0.1Omega

Two wires with resistances R and 2 R are connected in parallel, the ratio of heat generated in 2 R and R is

Two resistances R and 2R are connected in parallel in an electric circuit. The thermal energy developed in R and 2R are in the ratio

Two students made two circuits A and B to determine the resultant resistance of two resistors R_(1) and R_(2) connected in series : All the components have been connected correctly in :

Two cells of equal e.m.f. E b ut of difference internal resistance r_(1) and r_(2) are connected in parallel and the combination is connected with an external resistance R to obtain maximum power in R. find the value of R

You take two resistors of resistance 2R and 3R and connect them in parallel in an electric circuit. Calculate the ratio of electric power consumed by 2R and 3R resistors.