"যদি `cos ec\ theta=2x` এবং `cottheta=2/x` হয়, তাহলে `2(x^2-1/(x^2))`"

If cos ec theta=2x and cot theta=(2)/(x), find the value of 2(x^(2)-(1)/(x^(2)))

If 2cos theta=x+1/x then 2cos^2 theta=

If 2costheta=x+1/x , then 2cos2theta= ?

If 3x=cos ec theta and (3)/(x)=cot theta find the value of 3(x^(2)-(1)/(x^(2)))

If cos theta =1/2 (x+1/x ) , then 1/2(x^(2) +1/(x^(2))) is equal to :

If 3x=cos ec theta and (3)/(x)=cot theta, then find the value of 3(x^(2)-(1)/(x^(2)))

If (a cot theta+b cos ec theta)=x and (b cot theta+a cos ec theta)=y then x^(2)-y^(2) is equal to:

If 4x=cos ec theta and (8)/(x)=cot theta then find the value of 4(x^(2)-(4)/(x^(2)))

If sec theta+tan theta=x, then tan theta=(x^(2)+1)/(x) (b) (x^(2)-1)/(x)( c) (x^(2)+1)/(2x) (d) (x^(2)-1)/(2x)

If sec theta-tan theta=x then prove that cos theta=(2x)/(1+x^2)