The equation of the curve passing through the point `(1,pi/4)` and having a slope of tangent at any point (x,y) as `y/x - cos^2(y/x)` is

2.The equation of the curve passing through the point (1 (pi)/(4)) and having slope of tangent at any point (x y) as (y)/(x)-cos^(2)(y)/(x) is 1) x=e^(1-tan(y/x)) 2) x=e^((1+tan(y/x)) 3) x=1-tan(y/x)4)y=e^(1-cot((y)/(x)))

2.The equation of the curve passing through the point (1 (pi)/(4)) and having slope of tangent at any point (x ,y) as (y)/(x)-cos^(2)((y)/(x)) is 1) x=e^(1-tan(y/x)) 2) x=e^(1+tan(y/x)) 3) x=1-tan(y/x) 4) y=e^(1-cot((y)/(x)))

Find the equation of a curve passing through the point (1,pi/4) if the slope of the tangent to the curve at any point P(x,y) is y/x-cos^2(y/x)

Equation of the curve passing through the point (4,3) and having slope is (y)/(2) at a point (x,y) on it is

Equation of the curve passing through the point (4,3) and having slope = y/2 at a point (x,y) on it is

Find the equation of the curve passing through the point (1,0) if the slope of the tangent to the curve at any point (x,y)is(y-1)/(x^(2)+x)

The equation of the curve passing through the point (1,1) such that the slope of the tangent at any point (x,y) is equal to the product of its co-ordinates is