CH 3 & CH 4 IMP MCQ

I. CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH II. CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3) III. CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3) IV. CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH V. CH_(3) - CH_(2) - O - CH_(2) - CH_(3) VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) VII. CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3) Identify the pairs of compounds which are functional group isomers

I. CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH II. CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3) III. CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3) IV. CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH V. CH_(3) - CH_(2) - O - CH_(2) - CH_(3) VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) VII. CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3) Identify the pairs of compounds that represents position isomerism.

I. CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH II. CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3) III. CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3) IV. CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH V. CH_(3) - CH_(2) - O - CH_(2) - CH_(3) VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) VII. CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3) Identify the pair of compounds that represents chain isomerism

I. CH_(3) - CH_(2) - CH_(2) - CH_(2) - OH II. CH_(3) - CH_(2) - underset(OH)underset(|)(CH) - CH_(3) III. CH_(3) - underset(OH) underset(|)overset(CH_(3))overset(|)(C) - CH_(3) IV. CH_(3) - underset(CH_(3))underset(|)(CH) - CH_(2) - OH V. CH_(3) - CH_(2) - O - CH_(2) - CH_(3) VI. CH_(3) - O - CH_(2) - CH_(2) - CH_(3) VII. CH_(3) - O - underset(CH_(3))underset(|)(CH) - CH_(3) Which of the above compounds form pairs of metamers ?

CH_(3)CH_(2)CH = CH_(2)" and "CH_(3)CH = CH - CH_(3) show

Hybridisation states of C in CH_(3) and CH_(4) are

What is the order of the boiling points of following alkanes explain (I). CH_(3)-(CH_(2))_(4)-CH_3 (II). CH_(3)-CH_(2)-CH(CH_(3))-CH_(2)-CH_(3) (III). CH_(3)-C(CH_(3))_(2)-CH_(2)-CH_(3)