If AB is a chord of a circle with center O, AOC is a diameter and AT is the tangent drawn at point A...

If AB is chord of a circle with centre O, AOC is a diameter and AT is the tangent at A as shown in figure. Prove that angleBAT=angleACB.

In figure, AB is a chord of the circle and AOC is its diameter such that angleACB=50^(@) . If AT is the tangent to the circle at the point A, then angleBAT is equal to

In figure, AB is a chord of the circle and AOC is the diameter such that angleACB=50^(@) . If AT is the tangent to the circle at the point A, then angleBAT is equal to : (a) 45^(@) , (b) 60^(@) , (c) 50^(@) , (d) 55^(@)

AB and CD are equal chords of a circle whose center is O,

AB is a chord of a circle with centre O and diameter 20 cm. If AB = 12 cm, find the distance of AB from O.

In the given figure A,B is a chord of the circle and AOC is its diameter ,such that angleACB=50^(@) .If AT is the tangent to the circle at the point A, then angleBAT is equal to :

If the length of a chord of a circle , which makes a angle 45^@ with the tangent drawn at one end point of the chord , is 6 cm , then the radius of the circle is :