रासायनिक अभिक्रियाएं एवं समीकरण - L23 | NCERT Discussion Part 2 | CLASS10 विज्ञान | 8AM Nishtha mam

Class 10 Science (Hindi) | Chapter 1 | रासायनिक अभिक्रियाएँ एवं समीकरण | Important Questions | Quick Revision

The following data : 2, 5, 15, 25, 20, 12, 8, 7, 6, 16, 21,17, 30, 32, 23, 40, 51, 15, 2, 9, 57, 19, 25 is grouped in the classes 0 –5, 5 –10, 10 –15 etc. Find the frequency of the class 20 –25.

A block A of mass 2 kg is placed over another block B of mass 8 kg and supported by a ledge L fixed on block B on its smooth surface as its extended part. If a force F=100 N is applied on block B , it starts moving on rough horizontal surface. Find the force exerted by block B on is 25 N . (Take g=10m//s^(2) )

A 19.6 g of a given gaseous sample contains 2.8 g of molecules (d = 0.75 g L^(-1)) , 11.2 g of molecules (d = 3 g L^(-1)) and 5.6 g of molecules (d = 1.5 g L^(-1)) . All density measurements are made at STP . Calculate the total number of molecules (N) present in the given sample. Report your answer in 10^(23) N Assume Avogardro's number as 6 xx 10^(23) .

Median of a distribution is the value of the variable which divides it into equal parts . In case of individual observations x_1,x_2 .. x_n , if the number of observations is odd, then median is the value of ((n+1)/2) th observation when the observations have been arranged in ascending or descending order of magnitude. In case of even number of observations median is the A.M. of the values of (n/2) th and (n/2+1) th observations, arranged in ascending or descending order of magnitude . The mode of distribution is that value of the variable for which the frequency is maximum . Median of the distribution 8,5,7,9,13,11,20,23 , 25 ,28 , 27 is

The marks obtained by 40 students of class IX in an examination are given below: 18, 8, 12, 6, 8, 16, 12, 5, 23, 2, 16, 23, 2, 10, 20, 12, 9, 7, 6, 5, 3, 5, 13, 21, 13, 15, 20, 24, 1, 7, 21, 16, 13, 18, 23, 7, 3, 18, 17, 16 Present the data in the form of a frequency distribution using the same class size, one such class being 15-20 (where 20 is not included)

The graph of compressibility factor (Z) vs. P for one mole of a real gas is shown in following diagram. The graph is plotted at constant temperature 273K. If the slope of graph at very high pressure ((dZ)/(dP)) is ((1)/(2.8))atm^(-1) , then calculate volume of one mole of real gas molecules (in L/mol) Given : N_(A)=6xx10^(23) and R=(22.4)/(273)L atmK^(-1)mol^(-1)