If the displacement x of a particle (in metre) is related with time (in second) according

The displacement of an oscillating particle varies with time (in seconds ) according to the equation y=(cm)= sin ((pi)/(2))(t/2 + 1/3) The maximum acceleration of the particle is approximately

Displacement Of Particle In Nth Second

The displacement of a particle from its mean position (in m) varies with time according to the relation y = 0.2 sin (10pit+1.5pi)cos(10pit+1.5pi) . The motion of the particle is

The displacement x (in metre ) of a particle in, simple harmonic motion is related to time t ( in second ) as x= 0.01 cos (pi t + pi /4) the frequency of the motion will be

The relation 3t=sqrt(3x)+6 describe the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero is

The relation 3t=sqrt(3x)+6 describes the displacement of a particle in one" direction where "x" is in metres and t in sec.The displacement,when velocity is zero,is meters.

The displacement x of a particle is dependent on time t according to the relation : x = 3 - 5t + 2t^(2) . If t is measured in seconds and s in metres, find its acceleration at t = 4s.

The displacement x of a particle is dependent on time t according to the relation : x = 3 - 5t + 2t^(2) . If t is measured in seconds and s in metres, find its velocity at t = 2s.