A person trying to lose weight (dieter ) lifts a 10 kg mass through 0.5m, 1000 times, A ssume th...

A person trying to lose weight by burning fat lifts a mass of 10 kg upto a height of 1 m 1000 times. Assume that the potential energy lost each time he lowers the mass is dissipated. How much fat will he use up considering the work done only when the weight is lifted up? Fat supplies 3.8 x 10^(7) J of energy per kg which is converted to mechanical energy with a 20% efficiency rate. Take g=9.8 ms^(–2) :

A person trying to lose weight by burning fat filts a mass of 10 kg upto a being of 1m 1000 time . Assume that the potential energy lost each time be lower the mass is dissipated . How much far will be use up considering the work done only when the weight is lifted up ? Far supplies 3.8 xx 10^(7) J of energy per kg wich is canverted to mechanical energy with x 20 % efficiency rate Take = 9.8 ms^(-2)

Water is poured from a height of 10m into a mepty vessel at the rate of 1 litre per second . If the weight of the vessel is 10 kg ten th weight indicated at time t=60s will be

A person of mass 60 Kg wants to lose 5 kg by going up and down a 10 m high stairs. Assume he burns twice as much fat while going up than coming down. If 1 kg of fat is burnt on expending 7000 kilo calories, how many times must be go up and down to reduce his weight by 5kg ?

A person of mass 60 kg wants to lose 5kg by going up and down a 10 m high stairs. Assume he burns twice as much fat while going up than coming down. If 1 kg of fat is burnt of expending 7000 k cal, how many times must he go up and down to reduce his weight by 5 kg ?

The work done by a person in carrying a box of mass 10 kg through a vertical height of 10 m is 4900 J. The mass of the person is -

An electric motor that can develop 1.0 hp is used is used to lift a mass of 25 kg through a distance of 10.0 m. What is the minimum time in which it can do this ? (Take g=10m//s^(2))

A lift starts from rest with a constant upward acceleration It moves 1.5 m in the first 0.4 A person standing in the lift holds a packet of 2 kg by a string Calculate the tension in the string during the motion .

The weight of any person on the moon is about 1//6 times that on the earth. He can lift a mass of 15 kg on the earth. What will be the maximum mass, which can be lifted by the same force applied by the person on the moon?

A person holds on a weight of 10 kg at a height of 5m above the ground for 5 minutes. Work done by him is