A path of uniform width is built around a circular park. The inner and outer sides of this circular park...

A path of uniform width surrounds a circular park. The difference of internal and external circumferences of this circular path is 132 metres. Its width is : (Take pi= (22)/(7) )

A path of uniform width surrounds a circular park. The difference of internal and external circumference of this circular path is 132 metres. Its width is : (Take pi = (22)/(7) )

A circular park has a path of uniform width around it. The difference between the outer and inner circumferences of the circular path is 132 m. Its width is (a) 20 m (b) 21 m (c) 22 m (d) 24 m

The area (in m^2 ) of a circular path of uniform width x metres surrounding a circular region of diameter d metres is .....

Prove that the area of a circular path of uniform width h surrounding a circular region of radius r is pih(2r+h) .

A square park has area 4356 m^2 . Taking its one round is same as taking one round of another circular park. Find the area of the circular park.

Prove that the area of a circular path of uniform width h surrounding a circular region of radius r is pi h(2r+h).

A particle is moving around a circular path with uniform angular speed (x) . The radius of the circular path is (r). The acceleration of the particle is:

Find the area of a circular park whose radius is 4.5 m