The vapor of pure benzene at a temperature and pressure of 0.850 bar can be mixed with 39 grams of 0.5 gram non-volatile solute.

The vapour pressure of pure benzene at a certain temperature is 0.850 bar. A non-volatile, non-electrolyte solid weighting 0.5 g when added to 39.0 g of benzene (molar mass 78 g mol^(-1) ). The vapour pressure of the solution then is 0.845 bar. What is the molar mass of the solid substance?

A sample of 20.0 g of a compound (molecular weight 120 )which is non electrolyte is dissolved in 10.0 grams of ethanol (C_(2)H_(5)OH) . If the vapour pressure of pure ethanol at the temperature used is 0.250 atm ,what is the vapour pressure of ethanol above the solution

Vapour pressure of solution containing 6 g of a non-volatile solute in 180 g water is 20.0 Torr. If 1 mole water is further added vapour pressure increases by 0.02. The ratio of vapour pressure of water and molecular weight of non-volatile solute is

The vapour pressure of pure benzene at a certain temperature is 262 bar . At the same temperature the vapour pressure of a solution containing 2 g of non - volatil , non -electrolytic solid in 100 g of benzene is 256 bar . What is the molecular mass of the solid ?

The vapour pressure of pure benzene at a certain temperature is 640 mm og Hg . A non-volatile non-electrolyte solid weighing 2.175 g added 39.0 g of benzene. The vapour pressure of the solution is 600 mm of Hg . What is the molecular weight of solid substance?

The vapour pressure of pure benzene at a certain temperature is 640 mm of Hg. A non volatile nonelectrolyte solid weight 0.175 g is added to 39.0 benzene. The Vapour pressure of the solution is 600 mm of Hg. What is molecular weight of solid substance?