What is projectile speed? Establish the formula for its horizontal range. For which projective angle...

Keeping the speed of projection constant, the angle of projection is increased from 0^(@) to 90^(@) . Then the horizontal range of the projectile

A projectile is projected with speed u at an angle theta with the horizontal . The average velocity of the projectile between the instants it crosses the same level is

A particle is projected with a velcity (u) so that its horizontal range isthrice the greatest heitht attained. What is its horizontal range?

The angle of projection at which the horizontal range and maximum height of projectile are equal is

(A projectile projected at an angle 30^(@) from the horizontal has a range R . If the angle of projection at the same initial velocity be 60^(@) , then the range will be

For a projectile projected at an angle _____the maximum height and horizontal range are equal.

The time of flight of a projectile is related to its horizontal range by the equation gT^(2)=2R .The angle of projection is?

The range of a projectile launched at an angle of 15^(@) with horizontal is 1.5km. The range of projectile when launched at an angle of 45^(@) to the horizontal is

Statement-1 : A man projects a stone with speed u at some angle. He again projects a stone with same speed such that time of flight now is different. The horizontal ranges in both the cases may be same. (Neglect air friction) Statement-2 : The horizontal range is same for two projectiles projected with same speed if one is projected at an angle q with the horizontal and other is projected at an angle (90^(@) theta) with the horizontal. (Neglect air friction)