AD is a diameter and AB is a chord of a circle. If AD = 34 cm, AB = 30 cm, then what is the center of the circle?

AD is the diameter of a circle and AB is a chord. If AD = 34 cm, AB = 30 cm, the distance of AB from the centre of the circle is

AD is a diameter of a circle and AB is a chord. If AD = 34cm, AB = 30cm, the distance of AB form the centre of the circle is

AB and CD are parallel chords of a circle 3 cm apart. If AB = 4 cm, CD = 10 cm, then what is the radius of the circle ?

O' is the centre of the circle, AB is a chord of the circle, OM_|_ AB . If AB= 20 cm, OM = 2sqrt(11) cm, then radius of the circle is

In the given figure, AB is a diameter of a circle and CD is perpendicular to AB, if AB = 10 cm and AE = 2 cm, then what is the length of ED ?

In the adjacent figure AD is a straight line. OP is perpendicular to AD and O is centre of both circles. If OA = 20 cm, OB = 15 cm and OP = 12 cm then what is the length of AB?

Quadrilateral ABCD is circumscribed to a circle. If AB=6cm , BC=7cm and CD=4cm then the length of AD is

In the figure (i) given below, O is the centre of the circle. AB and CD are the chords of the circle. OM is perpendicular to AB and ON is perpendicular to CD. AB=24 cm OM=5 cm, ON=12 cm. Find the, (i) radius of the circle (ii) length of chord CD (ii) In the figure (ii) given below, CD is diameter which meets the chord AB at E such that AE = BE = 4 cm.If CE = 3 cm, find the radius of the circle.

In the adjoining figure, O is the centre of circle and diameter AC = 26 cm . If chord AB = 10 cm , then the distance between chord AB and centre O of the circle is :