AC and BD are chords of a circle which bisect each other. Prove (i) AC and BD are diameters…

AC and BD are chords of a circle which bisect each other.Prove that (i) AC and BD are diameters (ii) ABCD is a rectangle.

AC and BD are chords of a circle which bisect each other.Prove that (i) AC and BD are diameters (ii) ABCD is a rectangle

AC and BD are chords of a circle which bisect each other.Prrove that (i) AC and BD are diameters,(ii) ABCD is a rectangle

AC and BD are chords of a circle that bisect each other.Prove that: AC and BD are diameters ABCD is a rectangle.

The centre of circle is O. AC and BD are chords of circle which intersect at P. If angleAOB=15^(@) and angleAPB=30^(@) then tan^(2)angleAPB+cot^(2)angleCOD is-

O is the centre of a circle.AC and BD are two chords of the circle intersecting each other at P.If /_AOB=15^(@) and /_APB=30^(@), then 3(tan^(2)/_APB+cot^(2)/_COD) is equal to