A particle starts motion from rest with uniform acceleration. This is distance x travel in first 2 seconds...

A particle starts moving from rest under uniform acceleration it travels a distance x in the first two seconds and a distance y in the next two seconds. If y=nx , then n=

A particle starts moving from rest under uniform acceleration.It travels a distance x in the first 2 sec and a distance in the next 2sec.If u=nx then n is

A particle starts moving from rest under a constant acceleration. It travels a distance x in the first 10 sec and distance y in the next 10 sec, then

The displacement (s)- velocity ( v ) graph of a particle if it starts moving from rest with a uniform acceleration which is parallel to its instantaneous direction of motion is

A body starting from rest moving with uniform acceleration has a displacement of 16 m in first 4 seconds and 9 m in first 3 seconds. The acceleration of the body is :

A particle starts from rest with uniform acceleration a . Its velocity after n seconds is v . The displacement of the particle in the two seconds is :

A particle starts moving from rest such that it has uniform acceleration a_0 during the 1st second of motion, uniform acceleration (a_0)/(2) during the 2nd second of motion, uniform acceleration (a_0)/(4) during the 3rd second of motion, and so on, such that it has uniform acceleration (a_0)/(2^(n-1)) during the nth second of motion If the displacement of the particle during the 5th second of motion is D_5 =(Ka_0)/(32) , the value of K is

A body starts from rest with a uniform acceleration ‘a'. Find the distance covered by the body in nth second.

A particle starts from rest with uniform acceleration a . Its velocity after 'n' second is 'v'. The displacement of the body in the last two second is