A particle starts motion from rest. If the distance traveled by the particle in 5th second is 9 meters, then...

A particle is projected vertically upward and moves freely under gravity.If the distance travelled by the particle in the 4^(th) second of its motion is twice of that in the 5^( th ) second,then the speed of projection is ?[g=10m/ s^(2) ]

The variation of velocity of particle moving along a straight line is shown in the figure. The distance travelled by the particle in 4th second is?

The variation of velocity of particle moving along a straight line is shown in the figure. The distance travelled by the particle in 4th second is

The motion of a particle is described by the equation at u = at .The distance travelled by the particle in the first 4 seconds

A particle is moving under a constant acceleration of 3m//s^(2) . The initial velocity of the particle is 10m/s. calculate the distance travelled by the particle is 5s and also in th 5th second of its motion.

A particle moves in a straight line from origin. Its velocity time curve is shown. Find the distance of particle at the =8sec. From the origin and the distance travelled by the particle during first 8 seconds.

The velocity-time graph of a particle in straight line motion is veloity-time graph of a particle in straight line motion is shown in. The particle starts its motion from origin. . The distance of the particle from the origin after 8 s is .

Speed time graph of a particle shown in figure. Find distance travelled by particle in 5 second .

A particle starts from rest and moves along a straight line with uniform acceleration. The ratio of distance travelled by the particle during the first three seconds to the distance travelled by the particle during the next three seconds is 3 о 2