Both the radii of curvature of a biconvex lens are 20 cm and the refractive index of the glass of the lens is 1.5.

A converging bundle of rays is intercepted by a biconcave lens. The radii of curvature of both surfaces are 20cm and the refractive index of the material of the lens is 1.5. If the rays originially converged to a point 10cm in front of the lens, where will they now converge after passing through the lens?

The radii of curvature of the faces of a double convex lens are 10 cm and 20. The refractive index of the glass is 1.5. What is the power of this lens (in units of dioptre)?

The radius of curvature of a thin planoconvex lens is 10 cm and the refractive index of its glass is 1.5. If the plane surface is silvered, then it will behave like a

The power of a biconvex lens is 10 dioptre and the radius of curvature of each surface is 10 cm. Then the refractive index of the material of the lens is

The radii of curvature of the two surfaces of a lens are 20cm and 30 cm and the refractive index of the material of the lens is 1.5 . If the lens is concave - convex, then the focal length of lens is

The radii of curvature of the two surface of a lens are 20 cm and 30 cm and the refractive index of the material of the lens is 1.5 . If the lens is concave - convex, then the focal length of the lens is :

The radii of curvature of the two surfaces of a lens are 20 cm and 30 cm and the refractive index of the material of the lens is 1.5. If the lens is concave -convex, then the focal length of the lens is