समतल x-y+z=5 से बिंदु (1,-2,-3) की दूरी रेखा x/2=y/3=z/(-6) के समानांतर मापी गई...

एक बिंदु की रेखा से दूरी|दो समांतर रेखाओं के बीच की दूरी|उदाहरण|सारांश

Add: 5x - 8y + 2z, 3z - 4y - 2x, 6y - z - x and 3x - 2z - 3y

2x+y-z=1 x-y+z=2 3x+y-2z=-1

2x-3y+5z=16, 3x+ 2y-4z= -4, x + y - 2z =- 3.

Add 2x - 3y + z , 5y - x + 7z and 3x - y - 6z.

The lines x/1=y/2=z/3 and (x-1)/(-2)=(y-2)/(-4)=(z-3)/(-6) are

2x + 3y + 3z = 5, x-2y + z = -4,3x-y-2z = 3

Find the S.D. between the lines : (i) (x)/(2) = (y)/(-3) = (z)/(1) and (x -2)/(3) = (y - 1)/(-5) = (z + 4)/(2) (ii) (x -1)/(2) = (y - 2)/(3) = (z - 3)/(2) and (x + 1)/(3) = (y - 1)/(2) = (z - 1)/(5) (iii) (x + 1)/(7) = (y + 1)/(-6) = (z + 1)/(1) and (x -3)/(1) = (y -5)/(-2) = (z - 7)/(1) (iv) (x - 3)/(3) = (y - 8)/(-1) = (z-3)/(1) and (x + 3)/(-3) = (y +7)/(2) = (z -6)/(4) .

Show that the lines : (i) (x -5)/(7) = (y + 2)/(-5) = (z)/(1) " " and (x)/(1) = (y)/(2) = (z)/(3) (ii) (x - 3)/(2) = (y + 1)/(-3) = (z - 2)/(4) and (x + 2)/(2) = (y - 4)/(4) = (z + 5)/(2) are perpendicular to each other .

x+y+z=1 x-2y+3z=2 5x-3y+z=3