DeltaABC and DeltaDEF are two triangles such that (AB)/(DE)=(BC)/(EF)=(AC)/(DF)=4/9 so ar(ΔABC)/ar(ΔDEF...

If DeltaABC and DeltaDEF are two tnangles such that (AB)/(EF)=(BC)/(FD)=(CA)/(DE)=3/4 then find ar(DeltaDEF): ar(DeltaABC) .

In Delta ABC and Delta DEF , we have (AB)/(DE)=(BC)/(EF)=(AC)/(DF)=5/7 , then ar (Delta ABC) : ar (Delta DFR) =?

Delta ABC=Delta DEF, Prove that (AB)/(DE)=(AB+BC+AC)/(DE+EF+DF)

DeltaABC and DeltaDEF are similar such that (AB)/(DE)=(BC)/(EF) . Area of the two triangles are respectively 16cm^(2) and 49cm^(2) . If BC=2sqrt(2)cm , then what is length of EF ?

Two triangles DeltaABC and Delta DEF are given such that AB"||"DE,BC"||"EFandAB=DE,BC=EF. "Show that"AC"||"DFandAC=DE

DeltaABC and DeltaDEF are equilateral triangles. If A(DeltaABC):A(DeltaDEF)=1:2 and AB=4 , find DE.

DeltaABC~DeltaDEF , then (AB)/(DE)=(……….)/(EF)