दिखाएँ कि 2 (AB + BC + AC) = PQ + PR + RQ

Let triangle ABC~ triangle QPR and (ar(triangle ABC))/(ar(triangle PQR))=1//16 . If AB= 12cm, BC=6cm and AC=9cm then PR is equal to: माना कि triangle ABC~ triangle QPR और (ar(triangle ABC))/(ar(triangle PQR))=1//16 है| यदि AB= 12cm, BC=6cm और AC=9 cm है तो PR बराबर है:

In Delta ABC, AB= 4cm, AC = 5 cm and BC = 6 cm . In Delta PQR, PR = 4 cm, PQ = 5 cm and RQ = 6 cm. Delta ABC is congruent to

If in triangle triangleABC AB = 2cm, BC = 4 cm, and AC = 5 cm and in triangle trianglePQR PQ = 12 cm, QR = 24 cm , and PR = 30 cm then triangles are

Let triangle ABC ~ triangle QPR and (triangle ABC)/(triangle QPR)= 1/16 , If AB = 12 cm, BC =6 cm and AC = 9 cm, then PR is equal to: मान लीजिये कि triangle ABC ~ triangle QPR तथा (triangle ABC)/ (triangle QPR)= 1/16 हैं | यदि AB = 12 सेमी, BC = 6 सेमी और AC = 9 सेमी है, तो PR किसके बराबर है ?

Let triangle ABC ~ triangle QPR and (triangle ABC)/(triangle QPR)= 4/25 , If AB = 12 cm, BC =8 cm and AC = 9 cm, then PR is equal to: मान लीजिये कि triangle ABC ~ triangle QPR तथा (triangle ABC)/ (triangle QPR)= 4/25 हैं | यदि AB = 12 सेमी, BC = 8 सेमी और AC = 9 सेमी है, तो PR की लंबाई ज्ञात करें |

Let triangle ABC ~ triangle QPR and (triangle ABC)/(triangle QPR)=9/16 , If AB = 12 cm, BC =6 cm and AC = 9 cm, then PR is equal to: मान लीजिये कि triangle ABC ~ triangle QPR तथा (triangle ABC)/ (triangle QPR)= 9/16 हैं | यदि AB = 12 सेमी, BC = 6 सेमी और AC = 9 सेमी है, तो PR किसके बराबर है ?

Subtract : 2 ab + 5 bc - 7 ac from 5 ab - 2 bc - 2 ac + 10 abc

In DeltaABC , PQ is a line segment which intersect AB on P and AC on Q so that PQ||BC and divides DeltaABC in 2 equal parts of same area then find (BP)/(AB) .