`0.15 M NaOH` এর `27 mL`-এ `NaOH` এর কয়টি মোল রয়েছে?

100mL of 0.2M benzoic acid (pk_(a)=4.2) is titrated using 0.2 M NaOH pH after 50mL and 100mL of NaOH have been added are :

Are 0.5 mole of NaOH and 0.5 M of NaOH solution same ?

50 mL of 0.1 M HCl and 50 mL of 2.0 M NaOH are mixed. The pH of the resulting solution is

20mL of 0.5 M HCl and 35 mL of 0.1 N NaOH are mixed. The resulting solution will

A solution of weak acid HA was titrated with base NaOH. The equivalent point was reached when 40 mL. Of 0.1 M NaOH has been added. Now 20 mL of 0.1 M HCl were added to titrated solution, the pH was found to be 5.0 What will be the pH of the solution obtained by mixing 20 mL of 0.2 M NaOH and 20 mL of 0.2 M HA?

How many moles of NaOH are contained in 27 mL of 0.15 M NaOH ?

(a) Sample of NaOH weighing 0.38 is dissolved in water and the solution is made to 50.0 mL in a volumetric flask. What is the molarity of the resulting solution ? (b) How many moles of NaOH are contained in 27 mL of 0.15 M NaOH solution ?

Following solutions were prepared by mixing different volumes of NaOH and HCl of different concentrations: a. 60 mL (M)/(10) HCl + 40 mL (M)/(10) NaOH b. 55 mL (M)/(10) HCl + 45 mL (M)/(10) NaOH c.75 mL (M)/(5) HCl + 25 mL (M)/(5) NaOH d. 100 mL (M)/(10) HCl + 100 mL (M)/(10) NaOH pH of which one of them will be equal to 1 ?