There is a age difference of 10 years between two persons and 15 years ago the age of the elder was twice the age of the younger.

The difference between the ages of two persons is 10 years. 15 years ago the elder one was twice as old as the younger one. The present age of the elder person is

The difference between the ages of two cousins is 10 years. 15 years ago, if the elder one was twice as old as the younger one, find their present ages.

The difference between the ages of two men is 10 years. 15 years ago, the elder one was twice as old as the younger one. The present age of the elder man is a. 25 years b. 35 years c. 45 years d. 55years e. 52 years

The age of father is twice that of the elder son. After ten years, the age of father will be three times that of the younger son. If the difference of ages of the two sons is 15 years, the age of the father is?

The sum of the present ages of two cousins is 46 years. Eight years ago, the elder one was twice as old as the younger one. What is the present age of the elder cousin?

Two boys are playing on a ground. Both the boys are less than 10 years old. Age of the younger boy is equal to the cube root of the product of the age of the two boys. If we place the digit representing the age of the younger boy to the left of the digit representing the age of the elder boy, we get the age of father of the younger boy. Similarly, if we place the digit representing the age of the elder boy to the left of the digit representing the age of the younger boy and divided the figure by 2, we get the age of mother of the younger boy. The mother of the younger boy is younger to his father, by 3 years. Then, what is the age of the younger boy