The wavelength of a moving electron (lambda ) = 7.27 xx 10^(-10) meters. The energy of this electron...

Calcuate the wavelength of a moving electron having 4 . 55 xx 10 ^(-25) J of kinetic enrgy .

The de Broglie wavelength of an electron (m=9.11 xx 10^(-31) kg) is 1.2 xx 10^(-10)m . Determine the kinetic energy of the electron.

The de-Broglie wavelength of an electron is 0.4 xx 10^(-10) m when its kinetic energy is 1.0 keV. Its wavelength will be 1.0 xx 10^(-10) m, When its kinetic energy is

The wavelength of an electron of energy 10 keV will be :

The wavelength of an electron moving with velocity of 10^(7)ms^(-1) is

Calculate the ratio between the wavelength of an electron and a proton, if the proton is moving at half the velocity of the electron (mass of the proton =1.67xx10^(-27)kg , mass of the electron =9.11xx10^(-2)m .

What is the wavelength for the electron accelerated by 1.0 xx 10^(4) volts?

In an electron microscope, the resolution that can be achieved is of the order of the wavelength of electrons used. To resolve a width of 7.5 xx 10^(-12) m, the minimum electron energy required is close to :