The kinetic energy of an electron is 2.8xx10^(-23)J the de-Broglie wavelength will be approximately (m_(e)=9.1xx10^(...

The kinetic energy of one electron is 2.8xx10^(-13) J. What is the de-Broglie wavelength

An electron has kinetic energy 2.8 xx 10^-23 J de-Broglie wavelength will be nearly. (m_e = 9.1 xx 10^-31 kg) .

The kinetic energy of an electron is 5 eV . Calculate the de - Broglie wavelength associated with it ( h = 6.6 xx 10^(-34) Js , m_(e) = 9.1 xx 10^(-31) kg)

An electron in a hydrogen like atom is in an excited state3 . It has a total energy of -3 4 eV. Calculate : (a) The kinetic energy of electron . (b) The de-Broglie wavelength of electron . ( h = 6.6 xx 10^(023) , m_e = 9 .108 xx 10^(-31) kg)

If the KE of electron is 2.5 xx 10^(-24) J , then calculate its de-Broglie wavelength.

If kinetic energy of an electron is reduced by (1/9) then how many times its de Broglie wavelength will increase.

The kinetic energy of an electron is 4.55 xx 10^(-25)J . Calculate the wavelength . [h = 6.6 xx 10^(-34)Js , mass of electron = 9.1 xx 10^(-31)kg]

For what kinetic energy of a neutron will the associated de-Broglie wavelength be 5.6 xx 10^(-10)m ?

Find de-Broglie wavelength of electron with KE =9.6xx10^(-19)J .

The velocity of an electron with de Broglie wavelength of 1.0 xx 10^(2) nm is: