The weight of an object on Earth is 100 N. The mass of Mars is (1)/(10) and radius of Earth...

The weight of an object at the centre of the earth of radius R is

If weight of an object at pole is 196 N then weight at equator is [ g = 10 m/s^2 , radius of earth = 6400 Km]

The mass of planet mars is 1/10 th of the mass of earth and radius is 1/2 of the radius of earth. If the scape velocity at the earth is 11.2km/s, then the scape velocity at Mars will be

A body weights 100 kg on earth . Find its weight on mars . The mass and radius of mars are 1/10 and 1/2 of the mass and radius of earth .

How does the weight of an object vary with respect to mass and radius of the earth. In a hypothetical case, if the diameter of the earth becomes half of its present value and its ,mass becomes four times of its present value, then how would the weight of any object on the surface of the earth be affected?

The weight of an object on the moon is equal to of its weight on the earth.

The weight of a body on the suface of the earth is 100 N. The same at a height equal to a radius of the earth will be

What is the magnitude of the gravitational force between the Earth and a 1kg object on its surface ? (Mass of the earth is 6xx10^(24) kg and radius of the Earth is 6.4xx10^(6) m) .

Calculate the gravitational force on a body of mass 1 kg lying on the aurface of earth. Given mass of earth. Given mass of earth is 6xx10^(24) kg and radius of earth is 6400 km.

The binding energy of an object of mass m placed on the surface of the earth r is (R = radius of earth, g = acceleration due to gravity)