The gravitational acceleration (g) at the Earth's surface is 10 m/s^(2). The mass of Mars is less than that of Earth.

Let g be the acceleration due to gravity on the earth's surface.

A satellite of mass m is revolving around the Earth at a height R above the surface of the Earth. If g is the gravitational intensity at the Earth’s surface and R is the radius of the Earth, then the kinetic energy of the satellite will be:

The acceleration due to gravity on the surface of the earth is 10 ms^(-2) . The mass of the planet . Mars as compared to earth is 1/10 and radius is 1/2 . Determine the gravitational acceleration of a body on the surface on Mars .

The value of gravitational acceleration 'g' at a height 'h' above the earth's surface is (g)/(4) , then (R = __________ ) (where R = radius of the earth)

Acceleration due to gravity at earth's surface is 10 m ^(-2) The value of acceleration due to gravity at the surface of a planet of mass 1/2 th and radius 1/2 of f the earth is -

The gravitational potential energy of body of mass 'm' at the earth's surface mgR_(e) . Its gravitational potential energy at a height R_(e) fromt the earth's surface will be (here R_(e) is the radius of the earth)

The speed of a satellite that revolves around earth at a height 3R from earth's surface is ( g=10 m//s^(2) at the surface of earth, radius of earth R=6400 km ) in kms^(-1)

Assuming the mass of Earth to be ten times the mass of Mars, its radius to be twice the radius of Mars and the acceleration due to gravity on the surface of Earth is 10 m//s^(2) . Then the accelration due to gravity on the surface of Mars is given by

The gravitational potential energy of a body of mass ‘ m ’ at the earth’s surface -mgR_(e) . Its gravitational potential energy at a height R_(e) from the earth’s surface will be (Here R_(e) is the radius of the earth)