Light of wavelength 5000A falls perpendicularly on a slit 3xx 10^(-4) cm wide. Second conclusion...

Lights of wavelength 550 nm falls normally on a slit of width k 22.0 xx 10^(-5) cm . The angular position of the central maximum will be (in radian) :

The I^(st) different minimum due to single slit diffraction is theta , for a light of wave length 5000 Å . If the width of the slit si 1xx10^(-4) cm then the value of theta

Light wavelength 6000 Å is incident normally on a slit of width 24xx10^(-5) cm. find out the angular position of seconds minimum from central maximum?

Light of wavelength 5500 Å falls on a slit on a slit of width 0.13 cm at normal incidence. Calculate the width of the central maximum on a screen kept 2.5 m away from slit.

A beam of light of wavelength 600 nm from a distant source falls on a single slit 1.0 mm wide and the resulting diffraction pattern is observed on a screen 2 m away What is the distance between the second bright fringe on either side of the central bright fringe ?

Interference fringes were produced in Young's double slit experiment using light of wavelength 5000 Ã…. When a film of material 2.5xx 10^(-3) cm thick was placed over one of the slits, the fringe pattern shifted by a distance equal to 20 fringe widths. The refractive index of the material of the film is

Parallel light of wavelength 5000 Å falls normally on a single slit. The central maximum spreads out to 30^(@) on either side of the incident light.Find the width of the slit.For what width of the slit the central maximum would spread out to 90^(@) from the direction of the incident light ?

Light of wavelength 6000 o Ais incident normally on a slit of width 24 times 10^–5 cm. Find out the angular position of second minimum from central maximum ?