ગ્લાસ પ્રિઝમ (mu = sqrt(3)) માટે લઘુત્તમ વિચલનનો ખૂણો પ્રિના કોણ જેટલો છે...

A heavy body of mass 25kg is to be dragged along a horizontal plane (mu = (1)/(sqrt(3)) . The least force required is (1 kgf = 9.8 N)

For a glass prism (mu = sqrt(3)) the angle of minimum deviation is equal to the angle of the prism. Find the angle of the prism.

An equilateral prism of refractive index mu = (4)/(sqrt(3)) is kept in a medium of refractive index mu_(1) . Consider a light ray to be normally incident on one of the refracting faces. The diagram shows variation of magnitude of angle of deviation (beta) with respect to mu_(1) . (a) Find value of k_(2) . (b) Find value of k_(1) .

A ray of light incident on an equilateral triangular glass prism of mu = sqrt(3) moves parallel to the base of the prism inside it. What is the angle of incidence for this ray ?

Assertion: A body of weight 10N (W) is at rest on an inclined plane (mu=sqrt(3)/(2)) making an angle of 30^(@) with the horizontal. The force of friction acting on it is 5N Reason: In above situation, the limiting force of friction is given by f_("limitting")=mu W cos theta=7.5N .

In a condition of minimum deviation mu = sqrt(3) . Angle of incidence = 2 x angle of refraction then find angle of prism.

A ray of light is incident at an angle of 60 ^@ on a sqrt3 cm thick plate ( mu = sqrt3 ) The shift in the path of the ray as it emerges out from the plate is (in cm )

A cubical block rests on an inclined plance of mu = (1)/sqrt(3) . Determine the angle at which the block just slides down the incline .