A cell whose emf is 2 volts and internal resistance 0.1 Ohm, has an external resistance of 3.9 Ohm...

A student is asked to connected four cells of emf of 1 V and internal resistance 0.5 ohm in series with an external resistance of 1 ohm. But one cells is wrongly connected by him with its terminal reversed, the current in the ciruit is

The e.m.f. of a cell is 2.0 volt and the internal resistance is 0.1ohm. It is connected with a resistance of 3.9ohm. Then potential difference across the cell is :–

In the electric circuit shown each cell has an emf of 2 V and internal resistance of 1Omega . The external resistance is 2Omega . The value of the current is (in A)

A cell of emf epsilon and internal resistance r gives a current of 0.5 A with an external resistance of 12 Omega and a current of 0.25 A with an external resistance of 25 Omega . Calculate (a) internal resistance of the cell and (b) emf of the cell.

A potentiometer, wire of length 10m and resistance 21.8ohm is connected in series with a cell of emf 22 volt internal resistance 0.2omega and a Rheostate with maximum resistance of 22 ohm , then the minimum & maximum Potential gradient that can be obtained (V/m) are -

Four cell each of emf 2 V and internal resistance 1 ohm are connected n parallel with an external resistance of 6 ohm. The current in the external resistance is

A battery of emf 2 volts and internal resistance 0.1 ohm is being charged with a current of 5 amps. In what directions will the currents flow inside the battery? What is the potential difference between the two terminal of the battery?