Construct an arithmetic series by interposing 3 terms between 11 and –5. , 10 | Parallel series...

Insert six arithmetic means between 11 and -10.

Consider an arithmetic series and a geometric series having four initial terms from the set {11, 8, 21, 16, 26, 32, 4}. If the last terms of these series are the maximum possible four digit numbers, then the number of common terms in these two series is equal to "_______________"

In an arithmetic series, the sum of the first 2n terms is half the sum of the first 3n terms. If a = 12 and d = 3, find the value of n.

If the 14th term of an arithmetic series is 6 and 6th term is 14, then what is the 95th term?

If the first, second and last terms of an arithmetic series are a,b, and c respectively, then the number of terms is

If the first, second and last terms of an arithmetic series are a,b and c respectively , then the number of terms is

The 1^st, 2^nd and 3^rd terms of an arithmetic series are a, b and a^2 where 'a' is negative. The 1^st, 2^nd and 3^rd terms of a geometric series are a, a^2 and b find the (a) value of a and b (b) sum of infinite geometric series if it exists. If no then find the sum to n terms of the G.P. (c) sum of the 40 term of the arithmetic series.