Three capacitors of capacitance 10 pF are connected in series. If the combination is connected to 120 V supply (...

Three identical capacitors each of capacitance C are connected in series and this connection is connected in parallel with one such more identical capacitor. Then, the capacitance of the whole combination is

Two capacitors of capacites 1 mu F and C mu F are connected in series and the combination is charged to a potential difference of 120 V . If the charge on the combination is 80 muC , the energy stored in the capacitor C in micro joules is :

In the figure, three capacitors each of capacitance 6 pF are connected in series. The total capacitance of the combination will be

Three capacitors each of capacitance 1 muF are connected in parallel. To this combination, a fourth capacitor capacitance 1 muF is connected in series. The resultant capacitance of the system is

Three capacitors each of capacitance 1 mu F are connected in parallel.To this combination,a fourth capacitor of capacitance 1 mu F is connected in series.The resultant capacitance of the system

Three capacitors of capacitances 1muF,2muF and 4muF are connected first in a series combination, and then in parallel combination. The ratio of their equivalent capacitances will be

Three capacitors of 3muF each are connected in series. This combination is connected in series to another combination of three capacitors of 1muF each in parallel. Find the total capacitance.

Three capacitors of capacitance 3 muF, 10 muF and 15 muF are connected in series to a voltage source of 100 V . The charge on 15 muF is

Two capacitors of capacitances C_(1)=2muF and C_(2)=8muF are connected in series and the resulting combination is connected across a 300V battery. Calculate the charge, potential difference and energy stored in the capacitor separately.