If 25mL of a `H_(2)SO_(4)` solution reacts completely with `1.06g` of pure `Na_(2)CO_(3)` ,

Calcualte the volume of 0.324 M aq . H_(2) SO_(4) required to react completelty with 2.9792g of Na_(2) CO_(3) .

Standardization of Acid Solution: Calculate the normality of a solution of H_(2)SO_(4) if 40.0 mL of the solution reacts completely with 0.364 gram of Na_(2)CO_(3) . Strategy: Refer to the balanced equation. We are given the mass of Na_(2)CO_(3) , so we convert grams of Na_(2)SO_(3) to equivalents of Na_(2)CO_(3) , then to equivalents of H_(2)SO_(4) , which let us calculate the normality of the H_(2)SO_(4) solution.

If 100 mL "of" 1 M H_(2) SO_(4) solution is mixed with 100 mL of 98% (W//W) of H_(2)SO_(4) solution (d = 0.1 g mL^(-1)) , then

A 25mL HCl solution containing 3.65g HCl/L is neutralized by 50mL of NaOH solution. Again, 25mL of an H_(2)SO_(4) solution of unknow strenght. The normally of the H_(2)SO_(4) solution is :