`H_(2), Cl_(2)` এবং `HCl` এর বন্ড ডিসোসিয়েশন এনথালপি হল `434,242` এবং `431kJ mol^(-1)`

Bond dissociation enthalpy of H_(2),Cl_(2) and HCl are 434,242 and 431kJ mol^(-1) respectively. Enthalpy of formation of HCl is :

Bond dissociation enthalpy of H_(2) , Cl_(2) and HCl are 434, 242 and 431KJmol^(-1) respectively. Enthalpy of formation of HCl is

Calculate enthalpy of formation of HCl if Bond enthalpies of H_2, Cl_2 and HCl are 434 kJ mol^(-1) , 242 kJ mo l^(-1) and 431 kJ mol^(-1) respectively.

Calculate Delta G (in kJ) for the reaction at 300 K, H_(2)(g)+Cl_(2)(g) rarr 2HCl (g) Given at 300 K, BE_(H-H) = 435 kJ mol^(-1), BE_(Cl-Cl) = 240 kJ mol^(-1), BE_(HCl) = 430 kJ mol^(-1) Entropies of H_(2), Cl_(2) and HCl are 131, 223 and 187 JK^(-1) mol^(-1) respectively.

If S^(@) for H_(2),Cl_(2) and HCl are 0.13, 0.22 and 0.19 KJ K^(-1)mol^(-1) respectively. The total change in standard entropy for the reaction H_(2)+Cl_(2)rarr 2HCl is :-

Calculate free energy change for the reaction, H_(2)(g)+Cl_(2)(g)to2H-Cl(g) By using the bond energy and entropy data. Bond energies of H-H,Cl-Cl and H-Cl bonds are 435kJ mol^(-1),240jK" "mol^(-1) and 430jk" "mol^(-1) respectively standard entropies of H_(2),Cl_(2) and HCl are 130.59,222.95 and 186.68 JK^(-1)" "mol^(-1) respectively.

Determine enthalpy change for the reaction, CH_(4(g))+Cl_(2(g))rarr CH_(3)Cl_((g))+HCl_((g)) Bond energies for C-H,C-Cl,Cl-Cl,H-Cl are 412,338,242,431k J mol^(-1) respectively.