A straight highway leads to the foot of a 50 meter high tower. Two standing on the highway from the top of the tower...

A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at angle of depression of 30^0, which is approaching to the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60^0dot Find the further time taken by the can to reach the foot of the tower.

A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at angle of depression of 30o , which is approaching to the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60o . Find the further time taken by the car to reach the foot of the tower.

A straight highway leads to the foot of a tower. A man standing at the top of the tower observes a car at an angle of depression of 30^@ , which is approaching the foot of the tower with a uniform speed. Six seconds later, the angle of depression of the car is found to be 60^@. Find the time taken by the car to reach the foot of the tower from this point.

A straight highway leads to the foot of a tower of height 50m .From the top of the tower,the angles of depression of two cars standing on the highway are 30o and 60o respectively. What is the distance between the two cars and how far is each car from the tower?

A straight highway leads to the foot of a tower of height 50m. From the top of tower,the angles of depression of two cars standing on the highway are 30^(@) and 60^(@) respectively. What is the distance between the two cars and how far is each car from the tower?

The angle of elevation of the top of a 15 meters high tower from a point 15 metres aways from its foot is:

From the foot of a tower 90m high, a stone is thrown up so as to reach the top of the tower. Two second later another stone is dropped from the top of the tower. Find when and where two stones meet (Take g = 10 m//s^(2) )