A electron of hydrogen atom on an excited state is having energy `E_(n)=-0.85eV` .The maximum number of allowed transitions to lower energy level is_____________

The energy of a hydrogen atom in its ground state is -13.6 eV. What is the quantum number of the orbit corresponding to the energy level of -0.85 eV?

A hydrogen atom is in a state of ionization energy 0.85 eV. If it makes a transition to the ground state, what is the energy of the emitted photon.

An electron in hydrogen atom is in the n=4 energy level. When it makes a transition to some lower energy level, to which series the wavelength of emitted photon belong?

A hydrogen atom in a state having a binding energy of 0.85 eV makes transition to a state with excitation energy 10.2 eV. The quantum number n of the upper and the lower energy states are

A hydrogen-like atom in its first excited state has excitation energy of 91.8 eV. The energy required to remove the electron from its ion is:

The ground state energy of hydrogen atom is -13.6eV . The energy of excited state He^(+) ion having principal quantum number n is , -6.04eV . The numerical value of n is ________.

An electron jumps from 5^(th) excited level to 2^(nd) excited level in hydrogen atom. Maximum number of lines obtained in this transition will be

Consider a hydrogen-like atom whose energy in nth excited state is given by E_(n) = -(13.6 Z^(2))/(n^(2)) When this excited makes a transition from excited state to ground state , most energetic photons have energy E_(max) = 52.224 eV . and least energetic photons have energy E_(max) = 1.224 eV Find the atomic number of atom and the intial state or excitation.