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A bob of mass ‘m’ is suspended by a ligh...

A bob of mass ‘m’ is suspended by a light string of length ‘L’. It is imparted a minimum horizontal velocity at the lowest point A such that it just completes half circle reaching the top most position B. The ratio of kinetic energies `frac{(K.E.)_A}{(K.E)_B}` is

A

0.12638888888889

B

0.20902777777778

C

0.086805555555556

D

0.045138888888889

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The correct Answer is:
B
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