A parallel plate capacitor with plate separation "5mm" is charged up by a battery.It is found that on introducing a dielectric sheet of thickness "2mm" ,while keeping the battery connections intact,the capacitor draws "25%" more charge from the battery than before.The dielectric constant of the sheet is

A parallel plate capacitor of plate are A and plate separation d is charged by a battery of voltage V. The battery is then disconnected. The work needed to pull the plates to a separation 2d is

A parallel plate capacitor of capacity 5 mu F and plate separation 6 cm is connected to a 1V battery and is charged. A dielectric of dielectric constant 4 and thickness 4 cm is introduced into the capacitor. The additional charge that flows into the capacitor from the battery is.

A parallel plate capacitor is charged by a battery. The battery is removed and a thick glass slab is inserted between the plates. Now,

A parallel plate capacitor (C=50 muF. d=4mm) is charged to 200V and then charging battery is removed. Now a dielectric slab (K=4) of thickness 2mm is placed between the plates. Find new potential difference across capacitor.

A parallel plate condenser with plate separation d is charged with the help of a battery so that U_(0) energy is stored in the system. A plate of dielectric constant K and thickness d is placed between the plates of condenser while battery remains connected. The new energy of the system will be-

A parallel-plate capacitor of plate area A and plate separation d is charged by a ideal battery of e.m.f. V and then the battery is disconnected. A slab of dielectric constant 2k is then inserted between the plates of the capacitor so as to fill the whole space between the plates. Find the change in potential energy of the system in the process of inserting the slab.

A parallel plate capacitor is connected across a battery. Now, keeping the battery connected, a dielectric slab is inserted between the plates. In the process,

A parallel-plate capacitor having plate are 100 cm ^2 and separation 1.0 mm holds a charge of 0.12 muC when connected to a 120 V battery. Find the dielectric constant of the material filling the gap.