A particle moving in a circle of radius R with a uniform speed takes a time T to complete one revolution. If this particle were projected with the same speed at an angle `theta` to the horizontal, the maximum height attained by it equals 4R. The angle of projection `theta` is then given by

Options

A. `sin^(-1)[frac{2gT^2}{pi^2R}]^(1/2)`
B. `sin^(-1)[frac{pi^2R}{2gT^2}]^(1/2)`
C. `cos^(-1)[frac{2gT^2}{pi^2R}]^(1/2)`
D. `cos^(-1)[frac{pi^2R}{2gT^2}]^(1/2)`

Answer

A