Find the maximum profit that a company can make, if the profit function is given by `P(x) = 72 + 42x - x^2`, where x is the number of units and P is the profit in rupees.

Find the maximum profit that a company can make, if the profit function is given by : P(x)=41-72x-18x^(2)

Find the maximum profit that a company can make, if the profit function is given by : P(x)=41-24x-6x^(2).

Find the maximum profit that a company can make, if the profit function is given by : p(x)=41-72x-18x^(2) .

Find the maximum profit that a company can make,if the profit function is given by p(x)=41-24x-18x^(2)

Find the maximum profit that a company can make,if the profit function is given P(x)=41+24x-18x^(2)

The maximum profit that a company can make if the profit function is given by p(x) = - 18x^(2) + 36x+27 is :

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the maximum profit which can manufacturer earn?

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the break even point ? (Zero profit point is called break even)

Maximum profit: An barrels manufacturer can produce up to 300 barrels per day. The profit made from the sale of these barrels can be modelled by the function P(x) = -10x^(2) +3500x -66000 where P(x) is the profit in rupees and x is the number of barrels made and sold. Based on this model answer the following questions: What is the profit/loss if 400 barrels are produced