L2 Binding energy per nucleon

The amount of energy released in the fusion of two ._(1)H^(2) to form a ._(2)He^(4) nucleus will be {Binding energy per nucleon of ._(1)He^(2)=1.1 MeV Binding energy per nucleon of ._(2)He^(4)=7 MeV ]

Statement: Binding energy per nucleons becomes almost constant at 7.6 for elements beyond Pb and onwards. Explanation: The lower value of binding energy/nucleons is responsible for decay of transuranic elements.

Binding energy per nucleon of fixed nucleus X^(A) is 6 MeV . It absorbs a neutron moving with KE= 2 MeV and converts into Y at ground state, emitting a photon of energy 1 MeV . The Binding energy per nucleon of Y (in MeV) is -

Assertion: Lower value of binding energy per nucleon indicates greater stability. Reason : Binding energy per nucleon of ._(3)Li^(7) is greater than that of ._(2)He^(4) . Hence ._(3)Li^(7) is less stable than ._(2)He^(4) .

Statement: ._(26)^(56)Fe is most stable nucleus. Explanation: Binding energy per nucleon is maximum for ._(926)^(56)Fe

Assertion : Binding energy per nucleon is of the order of MeV. Reason: 1 MeV=1.6xx10^-13J .

The binding energy per nucleon is largest for

The value of binding energy per nucleon is