Equation of path of a projectile

The equation of a path of a projectile which is a projected with a velocity (V_(0)) at an angle 0 with horizontal is (x and y are horizontal and vertical displacement respectively)

What will be the equation for the path of a projectile if it is fired with initial velocity of (2hati+3hatj) . Here hatu and hatj are unit vectors along X-axis and Y-axis (g=10ms^(-2)) .

The pathe of a projectile is

At the highest point of the path of a projectile, its

At the highest point of the path of a projectile, its

The equation of motion of a projectile is y = 12 x - (3)/(4) x^2 . The horizontal component of velocity is 3 ms^-1 . What is the range of the projectile ?

The equation of the path of the projectiles is y=0.5x-0.04x^(2) .The initial speed of the projectile is? (g=10ms^(-2))

If y=x-x^(2) is the of the path of a projectile, then which of the following is incorrect: