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Coordinate Of A Particle After A Given Time t|Velocity And Direction Of Motion After A Given Time|Velocity And Direction Of Motion After At A Given Height|Questions|Equation Of Trajectory|Questions

Coordinate Of A Particle After A Given Time t|Velocity And Direction Of Motion After A Given Time|Velocity And Direction Of Motion After At A Given Height|Questions|Equation Of Trajectory|Questions

Coordinate Of A Particle After A Given Time t|Velocity And Direction Of Motion After A Given Time|Velocity And Direction Of Motion At Given Height|Exercise Questions|Equation Of Trajectory

Coordinate Of A Particle After A Given Time t|Velocity And Direction Of Motion After A Given Time|Velocity And Direction Of Motion At Given Height|Exercise Questions|Equation Of Trajectory

The velocity time graph of the motion of a car is given here.

A particle moves so that s=6+48t- t^3 . The direction of motion reverses after moving a distance of

The velocity time relation of a particle is given by v = (3t^(2) -2t-1) m//s Calculate the position and acceleration of the particle when velocity of the particle is zero . Given the initial position of the particle is 5m .

A particle moves with an initial velocity v_(0) and retardation alphav, where alpha is a constant and v is the velocity at any time t. If the particle is at the origin at t=0 , find (a) (i) velocity as a function of time t. (ii) After how much time the particle stops? (iii) After how much time velocity decreases by 50% ? (b) (i) Velocity as a function of displacement s. (ii) The maximum distance covered by the particle. (c ) Displacement as a function of time t.