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Initially spring is at it's natural length and collision is elastic. Then find maximum compression of spring during motion :

Consider the system shown below, with two equal masses m and a spring with spring constant K . The coefficient of friction between the left mass and horizontal table is mu=1//4 , and the pulley is frictionless. The spring connecting both the blocks is massless and inelastic. The system is held with the spring at its unstretched length and then released. If the string connecting both the masses is cut just at the instant both masses came to momentary rest for the first time in question 5, then maximum compression of spring during resulting motion is (Take mu=1//4 )

A particle of mass m collides elastically with the pan of mass (M = 2m) of a spring balance, as shown in figure. Pan is in equillibrium before collision. Spring constant is k and speed of the particle before collision is v_(0) . Answer the following three questions regarding this collision. Maximum compression in the spring after the collision the

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If blocks collide elastically head - on , the ratio of maximum compression of the left spring and the right spring will be

A block is released from height h , find the maximum compression of spring of spring constant k .

A block of mass m attached with a spring and held by a person such that the spring is in natural length l_(0) . Now the man releases the block, the ratio of maximum compression in the spring in the given situation , to that of the compression at equilibrium position.

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